Volume added at stoichiometric point

Moderators: Chem_Mod, Chem_Admin

AlexNguyen15
Posts: 66
Joined: Fri Sep 25, 2015 3:00 am

Volume added at stoichiometric point

Postby AlexNguyen15 » Tue Nov 24, 2015 2:53 pm

I've been trying to solve for the volume added at the stoichiometric point by doing the reverse of how I found the pH since I know the pH=7 but I'm stuck.
Can anyone explain if there is any easier process for this that I missed?

AlexNguyen15
Posts: 66
Joined: Fri Sep 25, 2015 3:00 am

Re: Volume added at stoichiometric point

Postby AlexNguyen15 » Tue Nov 24, 2015 4:09 pm

Also, what is considered the halfway point of the titration?

Anne Cam 3A
Posts: 71
Joined: Fri Sep 25, 2015 3:00 am

Re: Volume added at stoichiometric point

Postby Anne Cam 3A » Sat Nov 28, 2015 8:38 pm

The halfway point of a titration is when the concentrations of the acid and its conjugate base are equal, or the pKa = pH.

I assume that by "volume added at the stoichiometric point" you mean the volume added to reach the stoichometric point? Then you could follow the method in page 163 of the course reader: where you divide the moles of acid/base (at the stoichiometric point) by its molarity. That would give you the volume of the acid/base that was added to reach the stoichiometric point.


Return to “*Titrations & Titration Calculations”

Who is online

Users browsing this forum: No registered users and 4 guests