Stoichiometric point

[AlexNguyen15]

Q7 of Fall Final 2014:
The question asks which indicator to use for a titration of 0.20 M CH3COOH with 0.20 M NaOH. Ka = 1.8 x 10^-5
I know that at the stoichiometric point the moles of acid = moles of base, but I don't understand why the volume of the solution will have doubled at the stoichiometric point. Can anyone explain this to me?

[Nikhil Davuluri 2A]

Let's say you start out with 1L of .2 M CH3COOH. At the stoichiometric point you will have to add 1L of .2 M NaOH to get an equal number of moles. As a result the new solution will have a volume of 2L.
Hope this helps.