heat

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CenCen
Posts: 29
Joined: Fri Sep 25, 2015 3:00 am

heat

Postby CenCen » Mon Feb 08, 2016 5:37 pm

When solving for a problem that involves using the relation of qsurr=-qsys does it matter which side we place the negative sign? why? Thanks.

Chem_Mod
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Re: heat

Postby Chem_Mod » Mon Feb 08, 2016 7:52 pm

Put the negative sign where the heat is being lost. For example, if I put an ice cube in a glass of hot water. The heat is being lost by the hot water (-) and going to the ice cube to melt it essentially (+).


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