Homework Help 8.21

Moderators: Chem_Mod, Chem_Admin

Posts: 9
Joined: Wed Sep 21, 2016 2:55 pm

Homework Help 8.21

Postby Aiden_Hsu_1M » Sun Jan 15, 2017 6:06 pm

The problem states "A piece of copper of mass 20.0 g at 100.0ºC is placed in a vessel of negligible heat capacity but containing 50.7 g of water at 22.0ºC. Calculate the final temperature of the water. Assume that no energy is lost to the surroundings." I don't really know how to start this problem is there anyone who can just point me in the right direction for how to start it?

Posts: 18020
Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 418 times

Re: Homework Help 8.21

Postby Chem_Mod » Sun Jan 15, 2017 6:27 pm

First, you want to find heat capacities for both liquid water and copper. Next, realize that the descriptive terms provided in the problem are simply saying heat lost by the copper is equal to the heat gained by the water (i.e. the copper will cool down and the water will heat up). Try to solve it under that mindset.

Return to “Phase Changes & Related Calculations”

Who is online

Users browsing this forum: Areena H 2K, Prasanna Padmanabham 4I and 1 guest