Practice Quiz 1 #9

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Practice Quiz 1 #9

Postby Henry_Shin_3B » Mon Jan 30, 2017 7:26 pm

Why is delta S total positive? I'm having trouble understanding why the problem is a spontaneous process.

I understand that Ssys and G are 0 because they are both state functions, but why is the total entropy change positive?
What part of the problem gives that away?

Thank you.

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Re: Practice Quiz 1 #9

Postby Thomas_Rodriguez_3G » Mon Jan 30, 2017 7:49 pm

Because the piston expands while the gas is being heated, I believe. Its not stated explicitly, but I think thats the right answer.

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Re: Practice Quiz 1 #9

Postby Courtney_Koenig_3K » Thu Feb 02, 2017 7:52 pm

I think that since it says the reaction is an isothermal reaction, any energy that is lost from doing work is replaced in the form of heat from the surroundings. Since delta S(sys)= delta H(sys)/T, as T decreases, delta S(sys) increases to become positive.

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