Work equation

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Miriam Sheetz 2B
Posts: 64
Joined: Fri Sep 28, 2018 12:25 am

Work equation

Postby Miriam Sheetz 2B » Thu Feb 07, 2019 9:25 pm

Is there a constant to covert work from atm.L to J?
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Manu Vohra 1L
Posts: 61
Joined: Wed Oct 03, 2018 12:15 am

Re: Work equation

Postby Manu Vohra 1L » Thu Feb 07, 2019 9:27 pm

101.325 J = 1 atm(L)
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Abby-Hile-1F
Posts: 46
Joined: Fri Sep 28, 2018 12:16 am

Re: Work equation

Postby Abby-Hile-1F » Sun Feb 10, 2019 4:37 pm

It should be on the equation sheet.
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Tinisha 1G
Posts: 69
Joined: Fri Sep 28, 2018 12:17 am

Re: Work equation

Postby Tinisha 1G » Sun Feb 10, 2019 4:40 pm

You would multiply the amount of atm*L that you have by 101.325 J/atm*L to get your final answer in Joules.
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Luis_Yepez_1F
Posts: 50
Joined: Fri Sep 28, 2018 12:18 am

Re: Work equation

Postby Luis_Yepez_1F » Sun Feb 10, 2019 6:47 pm

I would look over the equation worksheet, then list out all the constants that aren't listed there and memorize them.
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