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Why is the work quantity in a isobaric process negative, in physics we have learned that w= +pdeltav... Can someone explain where the confusion comes from? Is this due to the fact we are using pressure external?
I don't know about physics portion of work but Lavelle said the negative sign is because its related to the work of the gas. For example imagine a gas system with a piston, and when the gas expands, delta V would be positive and therefore the work is negative meaning the gas DID work. When the delta V is negative, the work would be a positive value which means work was done on the system to push the gas and decrease the volume. Hope this helps zzz
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