Specific heat capacity of ice

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Clarissa Cabil 1I
Posts: 66
Joined: Fri Sep 28, 2018 12:19 am

Specific heat capacity of ice

Postby Clarissa Cabil 1I » Fri Mar 15, 2019 9:09 pm

When calculating q of ice combining with water, I know you would use the equation q = mCΔT + nΔHfus.
For C or specific heat, do I use the specific heat of water or ice? Why?

skyeblee2F
Posts: 62
Joined: Fri Sep 28, 2018 12:23 am

Re: Specific heat capacity of ice

Postby skyeblee2F » Fri Mar 15, 2019 9:40 pm

Think of it as two reactions occurring, where the ice (gains heat and) is undergoing a phase change to water and water (loses heat and) is undergoing a phase change to water. Thus you would have two identical equations equal to each other except for the specific heat and enthalpies.

ice: q(gain) = mC(solid)ΔT + nΔH(fus)
water: q(loss) = mC(liquid)ΔT + nΔH(freezing)

note that q(loss)=q(gain)
thus: mC(solid)ΔT + nΔH(fus) = mC(liquid)ΔT + nΔH(freezing)

eden tefera 2B
Posts: 39
Joined: Fri Sep 28, 2018 12:21 am

Re: Specific heat capacity of ice

Postby eden tefera 2B » Sat Mar 16, 2019 10:12 pm

Since each of them have their own phase change, you use that phase's specific heat capacity.


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