Enthalpy of sublimation?
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Enthalpy of sublimation?
Will we ever need to calculate the enthalpy of sublimation or use this value in any of our calculations? If so, how do you perform calculations using enthalpy of sublimation? Thank you!
Re: Enthalpy of sublimation?
The enthalpy of sublimation is simply the sum of the heat of fusion and the heat of vaporization.
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Re: Enthalpy of sublimation?
the enthalpy of sublimation is the sum of the enthalpy of vaporization and fusion
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Re: Enthalpy of sublimation?
Since enthalpy is a state function and sublimation means the subject goes from a solid to a gas, the enthalpy of sublimation=heat involved in fusion+heat involved in vaporization
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Re: Enthalpy of sublimation?
Understanding that you calculate the enthalpy of sublimation with the enthalpy of fusion and of vaporization lets you understand that enthalpy is additive, a state property. So for our purposes, it is helpful in that sense.
However, you'll probably see that we don't actually calculate the enthalpy of sublimation all too often, at least not immediately in the HW problems. Understanding the calculation of sublimation energy is kind of that real world application that you would actually study more of in a lab.
However, you'll probably see that we don't actually calculate the enthalpy of sublimation all too often, at least not immediately in the HW problems. Understanding the calculation of sublimation energy is kind of that real world application that you would actually study more of in a lab.
Re: Enthalpy of sublimation?
Ethalpy of sublimation is positive because it requires heat and therefore it would be endothermic. Also it is important to remember that phase changes are constant T.
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Re: Enthalpy of sublimation?
Vaporization, melting (fusion), and sublimation are all exothermic reactions, so the change of enthralpy of each of these three reactions has a positive value.
delta H(vap) = H(vapor) - H(liquid);
delta H(fus) = H(liquid) - H(solid);
delta H(sub) = H(vapor) - H(solid);
So delta H(sub) = delta H(fus) + delta H(vap).
delta H(vap) = H(vapor) - H(liquid);
delta H(fus) = H(liquid) - H(solid);
delta H(sub) = H(vapor) - H(solid);
So delta H(sub) = delta H(fus) + delta H(vap).
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Re: Enthalpy of sublimation?
Sublimation is the phase change from a solid directly to a liquid. Therefore, the enthalpy of sublimation is the change in enthalpy from a solid to a gas. The enthalpy of sublimation is the sum of the enthalpy of fusion and the enthalpy of vaporization: ΔH(sublimation) = ΔH(vaporization) + ΔH(fusion) = (H(gas) - H(liquid)) + (H(liquid) - H(solid)) = H(gas) - H(solid).
Re: Enthalpy of sublimation?
We will eventually have to calculate the enthalpy of sublimation and is represented by the sum of the heat of fusion and the heat of vaporization.
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