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4A.3

Posted: Wed Jan 29, 2020 10:29 pm
by RRahimtoola1I
Can someone please explain this problem. The solution manual is using 101.325J as a conversion but I'm not sure where they are getting it from. Other than that, I still don't understand the problem.

Re: 4A.3

Posted: Thu Jan 30, 2020 12:05 pm
by rachelle1K
The purpose of using 101.325 is to convert atm to Pa. In SI units, Pa is J.m^-3 . The equation used is w=PAD, and work is in joules, so the units would essential cancel out to joules because w=(J.m^3)(m^2)(m) .

Re: 4A.3

Posted: Thu Jan 30, 2020 6:37 pm
by Ellis Song 4I
You can find this number in the constants and equations paper. It converts 1 Latm to 101.325 J.

Re: 4A.3

Posted: Thu Jan 30, 2020 6:47 pm
by BritneyP- 2c
The textbook explains that the number comes from converting L*atm to Joules.