Week 4 Achieve 10

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Kaethe Zappacosta 2L
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Joined: Fri Sep 24, 2021 7:29 am

Week 4 Achieve 10

Postby Kaethe Zappacosta 2L » Wed Jan 26, 2022 7:19 pm

An ice cube with a mass of 52.6 g at 0.0 ∘C is added to a glass containing 359 g of water at 45.0 ∘C . Determine the final temperature of the system at equilibrium. The specific heat capacity of water, Cs , is 4.184 J/g⋅∘C , and the standard enthalpy of fusion, ΔH∘fus , of water is 6.01×103 J/mol . Assume that no energy is transferred to or from the surroundings


I found T final completely fine, but then the feedback told me that "the heat needed to melt the ice, ΔHfus , has not been accounted for. Calculate deltaHfus by multiplying the number of moles of ice by ΔH∘f . Then, factor this energy into the calculation.

Why do we need to do this, and why is delta Hfusion=-q(water)-q(ice)?

Anna Wilborn-1L
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Re: Week 4 Achieve 10

Postby Anna Wilborn-1L » Wed Jan 26, 2022 7:42 pm

The ice first needs to melt to liquid before the temperature of then melted ice can rise.

q melted ice + delta Hfusion = - q water because water is the surrounding and the ice is the system

Kathleen Wijaya 3L
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Re: Week 4 Achieve 10

Postby Kathleen Wijaya 3L » Thu Jan 27, 2022 12:45 am

∆Hfusion is important because the ice will undergo a phase change as it melts in the warmer water; we need to take this into account because it takes energy to melt ice.

305589333
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Re: Week 4 Achieve 10

Postby 305589333 » Fri Jan 28, 2022 1:53 pm

Ice will have to go through a phase change as the warm water causes it to melt which requires energy


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