Problem 8.37  [ENDORSED]

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Problem 8.37

Postby AsthaPatel4B » Fri Jan 20, 2017 5:07 pm

The problem states, "At its boiling point,the vaporization of 0.579mol CH4(l) requires 4.76 kj of heat. What is the enthalpy of vaporization of methane?"

My question: To solve this you would divide the heat by the moles(4.76kj/0.579mol). What is the reasoning behind dividing by moles?

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Re: Problem 8.37  [ENDORSED]

Postby EllisJang2O » Fri Jan 20, 2017 5:33 pm

I believe it's because you assume the question is asking for the (molar) heat of vaporization, in which the units are always kilojoules per mole.

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