HW 8.51

Moderators: Chem_Mod, Chem_Admin

Jasmine_Bagnas_1D
Posts: 10
Joined: Wed Sep 21, 2016 2:57 pm

HW 8.51

Postby Jasmine_Bagnas_1D » Sun Jan 22, 2017 3:16 pm

The question asks "The enthalpy of formation of TNT is -67 kj/mol and the density of TNT is 1.65 g/cm. In principle, it could be used as a rocket fuel, with the gases resulting from its decomposition streaming out of the rocket to give the required thrust. In practice, of course, it would be extremely dangerous as a fuel because it is sensitive to shock. Explore its potential as a rocket fuel by calculating its enthalpy density for the reaction: 4(C7H5N3O6)+21O2-->28CO2+10H2O+6N2." Can someone explain how to solve this, I keep getting the wrong sign for my answer.

Cinthia_Ramirez_3B
Posts: 10
Joined: Wed Sep 21, 2016 2:58 pm

Re: HW 8.51

Postby Cinthia_Ramirez_3B » Sun Jan 22, 2017 4:17 pm

Since the question asks to to calculate the enthalpy released per liter for the reaction (exothermic reaction), the negative sign is not necessary.


Return to “Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)”

Who is online

Users browsing this forum: No registered users and 2 guests