8.75b HOMEWORK PROBLEM

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Aleena_Sorf_2A
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Joined: Sat Jul 09, 2016 3:00 am

8.75b HOMEWORK PROBLEM

Postby Aleena_Sorf_2A » Sun Jan 22, 2017 4:12 pm

Why are the C=C bonds only breaking and not the C-H bonds for problem 8.75b?

shreya_mantri_3I
Posts: 17
Joined: Fri Jun 17, 2016 11:28 am

Re: 8.75b HOMEWORK PROBLEM

Postby shreya_mantri_3I » Sun Jan 22, 2017 5:14 pm

The easiest way to get the answer to such types of questions is to subtract ALL of the bonds that are formed from ALL of the bonds that are broken instead of trying to figure out which bonds remain bonded through the reaction and which bonds are broken.
So actually some hydrogen bonds arent broken as they remain in the product formed.

Stephanie_Thai_2C
Posts: 10
Joined: Fri Jul 22, 2016 3:00 am

Re: 8.75b HOMEWORK PROBLEM

Postby Stephanie_Thai_2C » Sun Jan 22, 2017 7:47 pm

It might be easier to understand/visualize the breaking/bonding aspects of the question by drawing out the lewis structures for the problem. When you draw the lewis structures for the reaction, you can see where new bonds form in the product and where bonds break in the reactants. Like the previous answer said, the C-H bonds in the reactant CH3CHCH2 remain when it becomes the product CH3CH(OH)CH3, so they do not need to break like the C=C or O-H bond does.


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