#75

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SaniShabgahi3N
Posts: 21
Joined: Wed Sep 21, 2016 2:57 pm

#75

Postby SaniShabgahi3N » Sun Jan 22, 2017 9:06 pm

Use the bond enthalpies in tables 8.6 and 8.7 to estimate the reaction enthalpy for CH3CHCH2(g) +H2O(g) --> CH3CH(OH)CH3(g). I know for the bonds broken, it's one double bond between two carbon atoms and 1 bond between O and H. However, for the bonds formed, I got one C-H bond, one C double bonded to O and one single C-O bond. Can someone explain my mistake?

Britney Pheng 1L
Posts: 22
Joined: Wed Sep 21, 2016 2:56 pm
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Re: #75

Postby Britney Pheng 1L » Sun Jan 22, 2017 9:52 pm

Hello!
I think your lewis structure for CH3CH(OH)CH3 is a bit off. The structure should have a total of 26 e-. The lewis structure that gives you a formation of a C=O bond will only have a total of 24 electrons, whereas if you attach the oxygen atom to only one carbon atom, you will get all 26 electrons. Hope this helps! :)
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