Question 27

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Robert Estrada
Posts: 50
Joined: Fri Sep 29, 2017 7:05 am

Question 27

Postby Robert Estrada » Thu Jan 11, 2018 7:18 pm

Could someone explain how you would setup number 27, " calculate the work for each of the following processes beginning with a gas sample in a piston assembly with T = 350 K, P = 1.79 atm and V = 4.29 L: (a) irreversible expansion against a constant external pressure of 1.00atm to a final volume of 6.52 L; (b) isothermal, reversible expansion to a final volume of 6.52 L."

Diego Zavala 2I
Posts: 65
Joined: Fri Sep 29, 2017 7:07 am
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Re: Question 27

Postby Diego Zavala 2I » Thu Jan 11, 2018 8:48 pm

For part a use the equation and for part b use equation w=-nRTln(V2/V1)

Humza_Khan_2J
Posts: 56
Joined: Thu Jul 13, 2017 3:00 am

Re: Question 27

Postby Humza_Khan_2J » Thu Jan 11, 2018 8:50 pm

You would need to use the fact that work of expansion against opposing constant pressure is equal to -PdeltaV. This yields (-1.00 atm)(6.52-4.29 L). The second part would require the isothermal expansion equation, which is also in the book. To get n in this case for the aforementioned equation, one would need to use PV=nRT.


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