8.73.b

Jeremiah Samaniego 2C
Posts: 33
Joined: Fri Sep 29, 2017 7:05 am

8.73.b

For homework question 8.73b we are given the chemical equation CH4 (g) + 4 Cl2 (g) --> CCl4 (g) + 4 HCl (g). In the solutions manual, it shows that we are breaking 4 mols of a C-H bond and we are forming 4 mols of a H-Cl bond. Can someone explain to me why there isn't only one mol being broken and formed for both bonds?

Ashley Macabasco 2K
Posts: 30
Joined: Fri Sep 29, 2017 7:05 am

Re: 8.73.b

I believe that 4 moles are broken in the C-H bond because there are four hydrogens bonded to one carbon in CH4 (lewis structure) so there are four C-H bonds and not one C-H bond. There are 4 moles of the H-Cl bond formed because of the 4 coefficient in "4 HCl" indicating that four H-Cl bonds will be formed.

Cassandra Mullen 1E
Posts: 54
Joined: Fri Sep 29, 2017 7:07 am
Been upvoted: 2 times

Re: 8.73.b

When determining the bond enthalpy, it helps to draw the molecules or at least visualize the individual bonds within each molecule. The bond enthalpies themselves are defined as the amount of energy to break one mole of the molecule. In this problem, there are four C-H bonds being broken and 4 H-Cl bonds being formed.

Yiwei Zhou 2I
Posts: 21
Joined: Fri Sep 29, 2017 7:07 am

Re: 8.73.b

Because 4 hydrogen atoms are bounded on C atom so the bond enthalpy should be multiplied by 4. You can also count every bond, broken or not, in the reactants and the products that it takes less time to think about the bond breaking and forming process.

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