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HW 8.45 (b)

Posted: Sat Jan 13, 2018 11:14 am
by Luke Bricca 1H
For question 8.45 part b, why is the enthalpy value found divided by the 4 moles of CS2? I know that the standard enthalpy of formation is per one mole formed of the product, but in the reaction there are 4 moles of carbon used to form 4 moles of CS2, so shouldn't the ratio be 1:1 and therefore the 4 moles of CS2 not factored into the equation?

Re: HW 8.45 (b)

Posted: Sat Jan 13, 2018 1:41 pm
by Curtis Tam 1J
The enthalpy change given is for every four moles of carbon reacted so that's why you must include that in your stoichiometric calculations :)