Homework Question 8.63 (c)

[Tia Tomescu 2D]

I checked my equations many times, but my value always comes to -38.72kJ while the answer is 15.28kJ. The previous two questions, (a) and (b) are similar to (c) and I used the same method: enthalpy of products - enthalpy of reactants. Does anyone know how to solve this?

[Curtis Tam 1J]

Smh tomato. Check solution manual errors.

[Miranda 1J]

you do DH= [(2DHf K2S)+(2DHf H2O)] - [(DHf H2S)+(2DHf KOH)] this should be =[-417.5 kJ/mol + 2(-285.83 kJ/mol)] - [-39.7 kJ/mol + 2(-482.37 kJ/mol)] = +15.28 kJ/mol

Hope that makes sense