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Abigail Urbina 1K
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Joined: Thu Jul 27, 2017 3:01 am


Postby Abigail Urbina 1K » Wed Jan 17, 2018 11:27 pm

How exactly are we supposed to approach part c in homework problem 8.45?
4 C(s) + S8(s) --> 4 CS2(l) deltaH=+358.8 kJ
c) If the heat absorbed in the reaction was 415 kJ, how much CS2 was produced?

Clarisse Wikstrom 1H
Posts: 63
Joined: Fri Sep 29, 2017 7:05 am

Re: 8.45

Postby Clarisse Wikstrom 1H » Wed Jan 17, 2018 11:37 pm

First you have to calculate the number of moles needed to produce that amount of heat absorbed. Since you know that q=n*deltaH, therefore n=(q)/(deltaH). this will give you moles per reaction, but you have to remember that there are 4 moles of CS2 produced per every reaction, so multiply what you got before by 4. It asks HOW MUCH, so assume they are looking for grams and then convert your moles CS2 to grams CS2.

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