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Posted: Sat Jan 20, 2018 2:35 pm
by Nishma Chakraborty 1J
This problem reads: Use the bond enthalpies in Tables 8.6 and 8.7 to estimate
the reaction enthalpy for (a) 3 C2H2(g) --> C6H6(g).

When we're calculating bonds broken vs. the bonds formed, why does the solutions manual not account for the C-H bonds?

Thank you!

Re: 8.73a

Posted: Sat Jan 20, 2018 2:41 pm
by Emily Glaser 1F
Think of a resonance structure, the C-H are bounded and when you have 3 moles of c2h2, you are not breaking those c-h bonds or forming. You are putting the c-c bonds together. Look up c6h6 on internet.