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Posted: Sat Jan 20, 2018 5:26 pm
by Emily Glaser 1F
I don't understand how the net moles produced was 2/3.

Also, where did the 1/3 applied to the delta H come from at the end of the solution?

Re: 8.117

Posted: Sun Jan 21, 2018 11:20 pm
by Yiwei Zhou 2I
For the production of 1.00 mol H2, you have 1/3 mol CH4, 1/3 mol H20, and 1/3 mol CO2 produced. So the net mole of gas is 2/3 mol.

Re: 8.117

Posted: Wed Jan 24, 2018 10:26 pm
by Adrian Lim 1G
The delta H given is for 1 mole of reaction or 3 moles of H2. However, the question is asking for the change for the production of only one mole. Thus, you would have to take the given delta H and divide it by 3