Why is the enthalpy of vaporization for this problem 4.76 kJ of heat/0.579 mol (from solution manual)?
Posted: Sun Jan 21, 2018 12:01 am
by Hazem Nasef 1I
That is how they calculated the enthalpy of vaporization because these values are always reported per 1 mole. If you divide the the heat by the number of moles, you'll get the enthalpy per mole, which is the standard way of reporting it.