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Posted: Sat Jan 20, 2018 11:34 pm
by Kassandra Molina 2B
Why is the enthalpy of vaporization for this problem 4.76 kJ of heat/0.579 mol (from solution manual)?

Re: 8.37

Posted: Sun Jan 21, 2018 12:01 am
by Hazem Nasef 1I
That is how they calculated the enthalpy of vaporization because these values are always reported per 1 mole. If you divide the the heat by the number of moles, you'll get the enthalpy per mole, which is the standard way of reporting it.