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If I'm understanding your question correctly, the value of the standard enthalpy of sublimation of carbon is, it's +717 kJ*mol^(-1), which was written in the question. If I didn't interpret your question correctly, can you clarify the question?
I'm pretty sure it's because when writing out the standard reaction equation for each of the compounds, carbon's standard state is C(gr) which is a solid, but in order to use bond enthalpies, carbon must be in a gaseous form, so the enthalpy of sublimation for carbon is to convert C(gr) -- solid -- into gas form.
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