8.75 part b

[Abigail Urbina 1K]

CH₃CHCH₂(g) + H₂O(g) --> CH₃CH(OH)CH₃(g)

I understand which bonds are broken and why (because I drew out the Lewis structures). However, for the bonds that are formed from this reaction, I am confused as to why the solution manual says that 1 mol of a C-C SINGLE bond is formed. Also, it says that 1 mol of a C-O SINGLE bond is formed when I thought that a C-O DOUBLE bond would be formed. I did, however, get 1 mol of the C-H single bond being formed. Can someone please clarify the other two bonds that were formed?

[sahajgill]

A C-C bond is formed because when the double bond C=C is broken, the C-C bond has to be reformed. It is not possible for one of the C=C bonds to be broken only. You are right about the C-H bond, but the other bond that forms is C-OH, which is not a double bond.

[Ammarah 2H]

I don't know if this will help, but for these problems, I find it easier to include all of the bonds in the calculation! I draw the Lewis structures and then count all the bonds for both the products and reactants. The math works out because the repeated bonds are subtracted out anyways.

[Adrian Lim 1G]

I also thought that there would be a C=O double bond formed. Can anyone please clarify?