4.D.11 (7th ed)

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1K Kevin
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Joined: Fri Sep 28, 2018 12:24 am

4.D.11 (7th ed)

Postby 1K Kevin » Tue Feb 05, 2019 3:32 pm

Part b asks "How much heat is absorbed in the oxidation of 5.45L of nitrogen measured at 1 atm and 273k?" The only thing I can think of is to use the ideal gas law because we have p v and t but that gives the the moles and where do we go from there?

Vy Lu 2B
Posts: 59
Joined: Fri Sep 28, 2018 12:24 am

Re: 4.D.11 (7th ed)

Postby Vy Lu 2B » Tue Feb 05, 2019 9:30 pm

What is the context of this problem's system? Is this process occurring isothermally or reversibly?

ChathuriGunasekera1D
Posts: 78
Joined: Fri Sep 28, 2018 12:17 am

Re: 4.D.11 (7th ed)

Postby ChathuriGunasekera1D » Tue Feb 05, 2019 9:33 pm

If you use PV = nRT you get 0.243 mol of N2. Using the standard enthalpy of formation of NO, you can say that the same amount of heat is released per mole of N2.

(0.243 mol)(180.6 KJ/mol) = 43.8 KJ


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