## 4.D.11 (7th ed)

1K Kevin
Posts: 47
Joined: Fri Sep 28, 2018 12:24 am

### 4.D.11 (7th ed)

Part b asks "How much heat is absorbed in the oxidation of 5.45L of nitrogen measured at 1 atm and 273k?" The only thing I can think of is to use the ideal gas law because we have p v and t but that gives the the moles and where do we go from there?

Vy Lu 2B
Posts: 59
Joined: Fri Sep 28, 2018 12:24 am

### Re: 4.D.11 (7th ed)

What is the context of this problem's system? Is this process occurring isothermally or reversibly?

ChathuriGunasekera1D
Posts: 78
Joined: Fri Sep 28, 2018 12:17 am

### Re: 4.D.11 (7th ed)

If you use PV = nRT you get 0.243 mol of N2. Using the standard enthalpy of formation of NO, you can say that the same amount of heat is released per mole of N2.

(0.243 mol)(180.6 KJ/mol) = 43.8 KJ

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