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In 8.49 of the 6th edition, we're asked to find the change in internal energy, knowing the reactions' change in enthalpy, and given the change in moles. We're not given a temperature, but we need a temperature to solve for work, or -p times delta V. We can solve for this using the ideal gas law. The temperature in the solutions manual is 298 degrees kelvin. Is this some kind of standard temperature for reactions? How was this number derived?
At standard conditions, temperature is 25 degrees Celsius or 298 K, so I would see if the question specifies that it takes place under standard conditions, because then you can assume the temperature to be 298 K. Pressure would be 1 atm and n would be 1 mol at standard conditions as well, so I would assume those if values are not given as well.
298 K is the standard temperature in an ideal gas equation and it is derived from 25 C + the conversion factor of 273. 298 seems like a random number but is in fact the Kelvin value in standard conditions.
Yes, 298 Degrees Kelvin is the standard for ideal gas.
It's part of the standard conditions of an ideal gas just as 1 atm is the condition for pressure
Standard conditions temp in kelvin! Because 25 C + 273
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