7th Edition 4.7

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7th Edition 4.7

Postby taywebb » Mon Feb 11, 2019 7:54 pm

For part c, the internal energy change of formation is the change in enthalpy of formation plus work. Why is this? I'm just confused on if the enthalpy of formation is replacing heat in this equation?

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Re: 7th Edition 4.7

Postby aisteles1G » Mon Feb 11, 2019 7:59 pm

You're right the question did not state constant pressure so it wouldn't be 100% safe to assume delta H = q but theres an equation: delta H= delta U + delta nRT, so following this since you have delta H and delta nRT (work) you can rearrange and solve for delta U!

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