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deltaU=0 when there is a constant temperature, or when temperature is 0. This is because of the equation U=3/2nRT. If constant temperature, Tf-Ti=0. However, if temperature=o, the equation would equal zero instantly.
I would just like to add that while delta U equals zero in an isothermal process (or in any isolated system), the two have no change in U for different reasons. In an isothermal process, the energy exchanged as heat (q) equals the amount of work done by the system (q = -w) so any heat energy from the process is cancelled out by work, and consequently delta U is 0. In an isolated system, no energy (either as work or as heatI is transferred, so q=0, w=0, and delta U = 0.
amogha_koka3I wrote:Do we assume isothermal, reversible, and at equilibrium are all synonymous in this class?
I believe that we can assume (for this class) that isothermal also means reversible. I don't think we can assume it's at equilibrium though.
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