HOTDOG problem

Moderators: Chem_Mod, Chem_Admin

Jasmin Argueta 1K
Posts: 69
Joined: Fri Sep 28, 2018 12:16 am

HOTDOG problem

Postby Jasmin Argueta 1K » Thu Feb 14, 2019 9:58 pm

In number 4A of the hotdog packet we didn't multiply the enthalpies by a negative when we flipped the reaction, does anyone know why? I thought we were suppose to multiply by a negative when we flipped the reaction because it's now the inverse.

Posts: 18901
Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 734 times

Re: HOTDOG problem

Postby Chem_Mod » Thu Feb 14, 2019 10:47 pm

Can you post the question in details?

Chris Freking 2G
Posts: 60
Joined: Fri Sep 28, 2018 12:29 am

Re: HOTDOG problem

Postby Chris Freking 2G » Fri Feb 15, 2019 11:26 am

You do flip the enthalpies when the equation is flipped. The final equation should be (2*-345kJ) + (2*21kJ) + (150kJ), where the first equation is multiplied by 2, the second equation is flipped and multiplied by 2, and the final equation is flipped as to give the final reaction 2GingerAle + 5RootBeer -> 2Vodka.

Posts: 6
Joined: Mon Apr 30, 2018 3:00 am

Re: HOTDOG problem

Postby avshi10b » Sun Mar 17, 2019 7:47 pm

Thank you

Return to “Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)”

Who is online

Users browsing this forum: No registered users and 1 guest