4D.15

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Summer de Vera 2C
Posts: 65
Joined: Fri Sep 28, 2018 12:16 am

4D.15

Postby Summer de Vera 2C » Fri Mar 15, 2019 2:14 am

For this problem, I am using the standard enthalpy of formations given and doing the summation of the products minus the summation of the reactants, however I'm producing a positive rather than negative value. Can anyone tell me why this is happening? Am I using the correct method?

605168557
Posts: 65
Joined: Fri Sep 28, 2018 12:18 am

Re: 4D.15

Postby 605168557 » Sat Mar 16, 2019 12:22 pm

First make sure your equations are balanced. The second equation is reversed and added to the first, plus 2x the third equation. When you do this the total change in enthalpy equation should look like this: -1300kJ.mol^-1 + 1560 kJ.mol^-1 + 2(-286 kJ.mol^-1) and when you calculate this you should get -312 kJ.mol^-1


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