4E.7

Moderators: Chem_Mod, Chem_Admin

ayushibanerjee06
Posts: 177
Joined: Thu Jul 11, 2019 12:16 am
Been upvoted: 1 time

4E.7

Postby ayushibanerjee06 » Thu Jan 30, 2020 9:30 pm

For the reaction: CH3CHCH2(g)+ 1H2O(g) -> CH3CH(OH)CH3(g)
I calculated that the bonds formed were: -7(c-h), -1 (c-c), -1(c=c), -2(o-h) and the bonds broken were: 6(c-h) + 2(o-h) + 1(c-c) + 1(c=c). I don't know why this is wrong.

AArmellini_1I
Posts: 107
Joined: Fri Aug 09, 2019 12:15 am

Re: 4E.7

Postby AArmellini_1I » Thu Jan 30, 2020 9:38 pm

Thats because you only need to break:
1 O-H (463kJ/mol) and 1 C=C (612kJ/mol)
And you form:
1 C-H -1(412) 1 C-O -1(360kJ/mol) and 1 C-C -1(348kJ/mol)
Add that all up and you get -45kJ/mol


Return to “Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)”

Who is online

Users browsing this forum: No registered users and 10 guests