C = K?

Moderators: Chem_Mod, Chem_Admin

gabbymaraziti
Posts: 111
Joined: Wed Sep 18, 2019 12:19 am

C = K?

Postby gabbymaraziti » Tue Feb 04, 2020 2:21 pm

Example 4A.4 in the textbook gives a change in temperature in celsius, then states that it is the same amount in kelvin. How is this possible?

Izzie Capra 2E
Posts: 103
Joined: Sat Sep 07, 2019 12:19 am

Re: C = K?

Postby Izzie Capra 2E » Tue Feb 04, 2020 2:23 pm

I think it means that when you raise the temperature by 1 degree C, that is the same thing as raising by 1 degree K, because they are on the same number scale.

AlyshaP_2B
Posts: 112
Joined: Wed Sep 18, 2019 12:19 am

Re: C = K?

Postby AlyshaP_2B » Tue Feb 04, 2020 2:24 pm

Even though the units are different, an increase of 1 unit Kelvin is equivalent to an increase of 1 unit Celsius. Since this equation uses delta T rather than just T, you can use the same number without having to do any conversions.

AveryAgosto
Posts: 76
Joined: Wed Sep 18, 2019 12:16 am

Re: C = K?

Postby AveryAgosto » Tue Feb 04, 2020 2:43 pm

We talked about it in discussion and it just means that it is scaled the same. If you were to add one degree to each that wouldn't change the ratio.

Philomena 4F
Posts: 27
Joined: Wed Feb 27, 2019 12:16 am

Re: C = K?

Postby Philomena 4F » Wed Feb 05, 2020 6:24 pm

It's the idea of raising the temp. by 1 degree C or K. You can use those scales interchangeably if the problem concerns delta T. Otherwise, a regular T in question would have different measured values for each scale.

IScarvie 1E
Posts: 66
Joined: Sat Aug 17, 2019 12:16 am

Re: C = K?

Postby IScarvie 1E » Wed Feb 05, 2020 6:30 pm

If the temperature raises from 25 to 27 C, by converting to K it is being raised from 298 to 300 K. However, the change in temperature for both is still 2. Therefore doesn't matter if you use kelvin or Celcius to measure delta T (unless you need to cancel out units later in the problem).


Return to “Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)”

Who is online

Users browsing this forum: No registered users and 2 guests