4E.7

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Amy Luu 2G
Posts: 105
Joined: Wed Sep 18, 2019 12:19 am

4E.7

Postby Amy Luu 2G » Tue Feb 04, 2020 8:55 pm

Use the data in Tables 4E.2 and 4E.3 to estimate the reaction enthalpy for
b) CH3CHCH2(g) + H2O(g) --> CH3CH(OH)CH3(g)
I am really confused on how to determine which bonds are broken/formed. I looked at all the bonds but the solution only used a few. how do we know which ones to use?

BNgo_2L
Posts: 95
Joined: Wed Sep 11, 2019 12:17 am

Re: 4E.7

Postby BNgo_2L » Tue Feb 04, 2020 9:17 pm

It's easier to tell if you draw the lewis structure of the entire reaction. In this case, one O-H is broken, and one C-O and one C-H bond is created.

Morgan Carrington 2H
Posts: 54
Joined: Wed Nov 14, 2018 12:22 am

Re: 4E.7

Postby Morgan Carrington 2H » Wed Feb 05, 2020 9:14 pm

Amy Luu 2G wrote:Use the data in Tables 4E.2 and 4E.3 to estimate the reaction enthalpy for
b) CH3CHCH2(g) + H2O(g) --> CH3CH(OH)CH3(g)
I am really confused on how to determine which bonds are broken/formed. I looked at all the bonds but the solution only used a few. how do we know which ones to use?


I also have a question on part a of this question. I'm not sure how exactly to determine the signs of the bond enthalpy values, so I keep getting the wrong answer. I know that the bonds of N2 and F2 have to be broken in order to form the NF bonds, but I'm lost from this point.


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