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Postby Goyama_2A » Thu Feb 06, 2020 5:28 pm

The questions asks to find the enthalpy change per liter for the reaction TNT and O2 to form CO2, H2O, and N2. I understand how they used the enthalpies of formation to find the enthalpy of the reaction to be -13168 kJ/mol. But, when they divide that by 4 to get the delta H per mole of TNT, they make the value positive instead of remaining negative. As a result, after turning that into the enthalpy per liter, my answer is the opposite sign of what the solutions manual gets. Why did they make the delta H positive?

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Re: 4D.9

Postby AKhanna_3H » Thu Feb 06, 2020 6:30 pm

I had the same question, but I found the answer in an endorsed post from Dr. Lavelle, if you scroll up to the announcements of this section it should be there.

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