4D.9

Moderators: Chem_Mod, Chem_Admin

Goyama_2A
Posts: 107
Joined: Sat Aug 24, 2019 12:17 am

4D.9

Postby Goyama_2A » Thu Feb 06, 2020 5:28 pm

The questions asks to find the enthalpy change per liter for the reaction TNT and O2 to form CO2, H2O, and N2. I understand how they used the enthalpies of formation to find the enthalpy of the reaction to be -13168 kJ/mol. But, when they divide that by 4 to get the delta H per mole of TNT, they make the value positive instead of remaining negative. As a result, after turning that into the enthalpy per liter, my answer is the opposite sign of what the solutions manual gets. Why did they make the delta H positive?

AKhanna_3H
Posts: 104
Joined: Wed Sep 18, 2019 12:19 am

Re: 4D.9

Postby AKhanna_3H » Thu Feb 06, 2020 6:30 pm

I had the same question, but I found the answer in an endorsed post from Dr. Lavelle, if you scroll up to the announcements of this section it should be there.


Return to “Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)”

Who is online

Users browsing this forum: No registered users and 1 guest