Textbook 4.29

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Tianna Nguyen 1I
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Joined: Fri Sep 24, 2021 7:09 am

Textbook 4.29

Postby Tianna Nguyen 1I » Sun Jan 23, 2022 3:25 am

Hi, I'm confused how the equation ΔHrxn=[2ΔHS + 2ΔHH2O] - [2ΔHH2S + ΔHO2] got reduced to ΔHrxn=2ΔHH2O - 2ΔHH2S. Why did 2ΔHS and ΔHO2 get reduced to 0 and what's the general rule for that?

Lauren Woodward 1I
Posts: 101
Joined: Fri Sep 24, 2021 6:13 am

Re: Textbook 4.29

Postby Lauren Woodward 1I » Sun Jan 23, 2022 10:47 am

The standard enthalpy of formation for elements in their most stable form is 0, so that's why S and O2 were removed.

Edwin Montalvo 1G
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Joined: Fri Sep 24, 2021 6:27 am

Re: Textbook 4.29

Postby Edwin Montalvo 1G » Sun Jan 23, 2022 12:19 pm

This is because the standard enthalpy of formation of 1 mole of a substance is defined as the energy required/released to form the substance from its elements in their most stable form. O2, for example, has a standard enthalpy of formation of 0 because to form O2 from its most stable form (O2) requires/releases 0 kJ of energy since it is already is in its most stable form.

Tianna Nguyen 1I
Posts: 100
Joined: Fri Sep 24, 2021 7:09 am

Re: Textbook 4.29

Postby Tianna Nguyen 1I » Mon Jan 24, 2022 2:34 pm

Thanks for your responses! Is there a way to know the most stable form of an element? Or is it just something we have to memorize?

Ethan Hung 2A
Posts: 103
Joined: Fri Sep 24, 2021 6:02 am

Re: Textbook 4.29

Postby Ethan Hung 2A » Mon Jan 24, 2022 3:43 pm

It seems like something that is memorized, though I would imagine unusual cases (i.e. not the common nonmetals like hydrogen, oxygen, carbon, etc.) would be stated in the problem.


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