Can someone run through this problem? I keep getting the wrong answer and I don't know why. From Appendix 2A, I get [6(-393.52kJ) + 3(-241.82kJ)] - 49kJ = -3135.52 kJ, but the book says the answer is -3267.5 kJ. Also, I don't understand how to do part C. Thanks you in advance!
Textbook Problem 4.7 [ENDORSED]
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Ryan Khiev 1L
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Textbook Problem 4.7
Can someone run through this problem? I keep getting the wrong answer and I don't know why. From Appendix 2A, I get [6(-393.52kJ) + 3(-241.82kJ)] - 49kJ = -3135.52 kJ, but the book says the answer is -3267.5 kJ. Also, I don't understand how to do part C. Thanks you in advance!
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Chem_Mod
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Re: Textbook Problem 4.7 [ENDORSED]
Delta U = qp + w
qp = Delta H
w = -P Delta V
Using PV = nRT one obtains: P Delta V = Delta n RT
Therefore, Delta U = Delta H - Delta n RT
Here are the numbers:
qp = Delta H
w = -P Delta V
Using PV = nRT one obtains: P Delta V = Delta n RT
Therefore, Delta U = Delta H - Delta n RT
Here are the numbers:
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