Question 8.117

Moderators: Chem_Mod, Chem_Admin

JukaKim_1D
Posts: 24
Joined: Fri Sep 25, 2015 3:00 am

Question 8.117

Postby JukaKim_1D » Mon Jan 18, 2016 2:13 pm

For question 8.117, why is it that the net mole change is 2/3 when the equation is CH4(g) + H2O(g) -> CO2(g) + 3H2(g)? Shouldn't the net mole change be 2?

Bryan Lau 3H
Posts: 53
Joined: Fri Sep 25, 2015 3:00 am

Re: Question 8.117

Postby Bryan Lau 3H » Mon Jan 18, 2016 7:30 pm

The question asks for the production of 1.00 mol H2. The equation given produces 3 mol H2, so you have to divide the equation by 3 to get just 1.00 mol H2. Two mol reactants becomes 2/3, and 4 mol products becomes 4/3. 4/3 - 2/3 = 2/3, and that's why ∆n = 2/3 :)


Return to “Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)”

Who is online

Users browsing this forum: No registered users and 2 guests