## value of n in w= -nRT*ln(V2/V1) vs. q=nCΔT

aristotelis1H
Posts: 16
Joined: Fri Sep 25, 2015 3:00 am

### value of n in w= -nRT*ln(V2/V1) vs. q=nCΔT

In some homework questions, the value of n in q = nCΔT is assumed to be equal to 1; however, when using w = $-nRT\mathit{ln}\frac{V2}{V1}$ you must solve for n by PV = nRT.
Why is this and is this always the case?

VictoriaRoderick_3A
Posts: 42
Joined: Fri Sep 25, 2015 3:00 am

### Re: value of n in w= -nRT*ln(V2/V1) vs. q=nCΔT

I believe this is the case simply because you are given the values to solve for n.

204280190
Posts: 11
Joined: Mon Jan 26, 2015 2:17 pm

### Re: value of n in w= -nRT*ln(V2/V1) vs. q=nCΔT

Keep in mind that nrtln(v2/v1) is derived from the ideal gas law (must be applied to ideal gases) while q=cdeltaT is for other substances