Midterm Winter 2011 #1

KaylaH
Posts: 26
Joined: Fri Sep 25, 2015 3:00 am

Midterm Winter 2011 #1

I don't understand how they got the equation to solve this question. Shouldn't the correct equation to solve for Ccal be $C_{cal}=\frac{q}{n\Delta T}$
. So, why did they write it differently? Also, for the units, shouldn't it be kJ/degrees C...not kJ.C?

Emma Edmond 3E
Posts: 29
Joined: Fri Sep 25, 2015 3:00 am

Re: Midterm Winter 2011 #1

The equation to solve for heat capacity of a calorimeter is $-q=C_{cal}\Delta T$. So to solve for q we must use the equation $q=n\Delta H$
q=nDeltaH and plug in moles of benzoic acid (found by dividing by the molecular weight) and the $\Delta$H that they gave us. We can then plug that in to q and divide by the change in temp to find the heat capacity of the calorimeter.

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