8.21 Homework Problem

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Jaime_Chamberlain_3G
Posts: 23
Joined: Sat Jul 09, 2016 3:00 am

8.21 Homework Problem

Postby Jaime_Chamberlain_3G » Sat Jan 14, 2017 6:45 pm

How would you go about doing 8.21 in the homework? "A piece of copper of mass 20.0 g at 100.0 C is placed in a vessel of negligible heat capacity but containing 50.7 g of water at 22.0 C. Calculate the final temperature of the water. Assume that no energy is lost to the surroundings."

Sangita_Sub_3H
Posts: 23
Joined: Sat Jul 09, 2016 3:00 am

Re: 8.21 Homework Problem

Postby Sangita_Sub_3H » Sat Jan 14, 2017 8:00 pm

Hi! So, since you know that 0 energy is lost to the surroundings, you then set up the primary equation q(copper)+ q(water) = 0, where q = m*C*delta T. However, since you are solving for temperature, the equation for copper would be q = (20.0g)*(0.38 J/(g*degrees C))*(T - 100 degrees C) and the equation for water would be q = (50.7g)*(4.184 J/(g*degrees C))*(T-22 degrees C) since the final temperature is unknown but the initial temperature is known. Then after plugging in these two equations into the primary equation, you should get the correct answer.

Hope this helps!


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