Problem 8.51

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Sydney Wu 2M
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Joined: Fri Jul 22, 2016 3:00 am

Problem 8.51

Postby Sydney Wu 2M » Fri Jan 20, 2017 6:19 pm

"The enthalpy of formation of TNT is -67 kJ.mol-1, and the density of TNT is 1.65 its potential as a rocket fuel by calculating its enthalpy density (enthalpy released per liter) for the reaction
4C7H5N3O6(s) + 21 O2(g) --> 28 CO2(g) + 10 H2O(g) + 6 N2(g)

I don't understand the thought process from the SSM. Couldn't I just convert the density to liters and divide the given values (since its enthalpy released per liter)?

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Re: Problem 8.51

Postby Sylvia_Cai_3D » Sat Jan 21, 2017 10:03 pm

Yes, you convert the density to liters, but included in the enthalpy value is the "per mole" part so you have to make the values' units match each other by changing the density value from grams to moles.

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