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Example 8.7 on Section 8.13

Posted: Sun Jan 22, 2017 1:42 am
by Byron_Corado_3D
Can somebody explain to me why in example 8.7 in section 8.13 they use deltaH=(q)x(2 mol/n) to find the thermochemical equation. I'm confused as to why they divided the 2 mol by n.

Re: Example 8.7 on Section 8.13

Posted: Sun Jan 22, 2017 11:20 am
by Selena_Wong_1I
Normally, the equation of delta H = q/n. The enthalpy change is usually referred to as the the enthalpy change PER mole. However, in this question, the moles of C6H6 is 2, not 1. Therefore, we must multiply 2 * q/n.