Question 8.19

Moderators: Chem_Mod, Chem_Admin

Sue_Park_2D
Posts: 13
Joined: Wed Sep 21, 2016 2:57 pm

Question 8.19

Postby Sue_Park_2D » Sun Jan 22, 2017 6:58 pm

I understand how to do part a in finding the amount of heat needed to raise the temperature of 400.0g of water in 500.0g copper kettlel from 22 to 100 degrees celsius. (q= 1.4 x 10^2 kJ)

However, I don't understand what it means in part b when it asks for the percentage of the heat used to raise the temperature of the heat. How could I start this?

Thank you
Last edited by Sue_Park_2D on Sun Jan 22, 2017 7:02 pm, edited 1 time in total.

104733470
Posts: 9
Joined: Wed Sep 21, 2016 3:00 pm

Re: Question 8.19

Postby 104733470 » Sun Jan 22, 2017 7:02 pm

you have to raise the temperature of both the liquid and the container so find the total heat of that and use it as the denominator with the heat used to raise the temp of the liquid as the numerator.

Sue_Park_2D
Posts: 13
Joined: Wed Sep 21, 2016 2:57 pm

Re: Question 8.19

Postby Sue_Park_2D » Sun Jan 22, 2017 7:08 pm

Oh, I see! Thanks for your explanation.


Return to “Heat Capacities, Calorimeters & Calorimetry Calculations”

Who is online

Users browsing this forum: No registered users and 3 guests