Ch 8 Problem 49

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Ch 8 Problem 49

Postby Maria1E » Thu Jan 11, 2018 9:45 pm

OF2 (g) + H2O (g) --> O2 (g) + 2HF (g)

Delta H is -318 kJ.
What is the change in internal energy for the reaction of 1.00 mol OF2?

I understand that we need to use the equation P(delta)V = (delta)nRT. However, I am confused about how we are supposed to know that the temperature is 298 K as stated in the solution manual. Thank you!

Kaylin Krahn 1I
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Re: Ch 8 Problem 49

Postby Kaylin Krahn 1I » Thu Jan 11, 2018 10:20 pm

For most equations we assume the temp is 25 degrees celsius, which is equivalent to 298K, so I think it was just assumed the equation took place at standard temperature since a temperature wasn't given.

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