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### 8.53

Posted: Sat Jan 13, 2018 2:13 pm
In example 8.53, why do we use q=C(change in T) rather than q=mC(change in T)?

### Re: 8.53

Posted: Sat Jan 13, 2018 2:53 pm
The solution involves using the heat capacity of the calorimeter, so we would use $q = C_{cal} \Delta T$, which doesn't require the mass of the calorimeter.

### Re: 8.53

Posted: Sat Jan 13, 2018 9:26 pm
For this problem, why do we need to take into account that q reaction is equal to -q calorimeter as it states in the solutions manual?