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This question explicitly asks to calculate the heat released. I was wondering how you know to find molar heat capacity (and thus you have to change the mass into number of moles, as shown in the solutions manual) rather than keeping the Kr in terms of grams.
As the response stated above iterates, since you know that Krypton is assumed to behave as an ideal gas, you must refer to the molar heat capacity constants for ideal gases under constant pressure and volume (in this case, 5/2R and 3/2R respectively. Using those values in q= n(molar heat capacity under constant volume OR pressure)(delta T), the amount of heat released may be calculated.
in page 281, it says that Cv,m= 3/2R . so you multiply both sides by m to make Cv,m just Cv. Then Cv= ΔU/ΔT. multiply both sides by ΔT and you get ΔU= 3/2R n ΔT. and ΔU is just q because w is 0 since there is no change in volume.
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