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### Question 8.31

Posted: Sat Jan 27, 2018 9:05 pm
Hi! I was looking at question 8.31 in the textbook and I was confused because for calculating both Cpm and Cvm the book used the R value 8.31 J/mol*K but uses the temperature change in degrees Celsius. Why is there such a discrepancy? Thanks!

### Re: Question 8.31

Posted: Sat Jan 27, 2018 9:35 pm
Because getting from Celsius to Kelvin is just adding 273.15, the difference between T2 and T1 in Celsius is going to be just the same as between T2 and T1 in Kelvin.

For example:
If the initial temp is 20 degrees Celsius, that is 293.15 K.
If the final temp is 40 degrees Celsius, that is 313.15 K.
So:
For Celcius, delta T= 40-20 = 20
For Kelvin, delta T= 313.15-293.15 = 20

### Re: Question 8.31

Posted: Sat Jan 27, 2018 11:22 pm
Since we're adding 273 to both the initial and final value of temperature, it doesn't matter if we use celsius or kelvin.

### Re: Question 8.31

Posted: Sat Jan 27, 2018 11:25 pm
The temperature change could be calculated either way using Kelvin or Celsius because regardless of which unit you use, the difference between the two temperatures will be the same.

### Re: Question 8.31

Posted: Sun Jan 28, 2018 2:49 pm
You can use either because adding 273 won't make a difference.

### Re: Question 8.31

Posted: Sun Jan 28, 2018 10:16 pm
Since you add 273 to both values, it would not interfere with the delta T value.

### Re: Question 8.31

Posted: Mon Feb 05, 2018 10:13 pm
If you do the caculation, the change of Celcius and the change in Kelvin will be the same.

### Re: Question 8.31

Posted: Sat Feb 10, 2018 9:44 am
Kelvin = 273 + Degree Celcius. So it doesn't matter if you use either since the temperature difference is the same for both units.